y^2=0.25y=

Solution for y^2=0.25y= equation:

y^2=0.25y=

We move all terms to the left:

y^2-(0.25y)=0

We add all the numbers together, and all the variables

y^2-(+0.25y)=0

We get rid of parentheses

y^2-0.25y=0

a = 1; b = -0.25; c = 0;
Δ = b2-4ac
Δ = -0.252-4·1·0
Δ = 0.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.25)-\sqrt{0.0625}}{2*1}=\frac{0.25-\sqrt{0.0625}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.25)+\sqrt{0.0625}}{2*1}=\frac{0.25+\sqrt{0.0625}}{2}
$